How do you solve i35?

1 Answer

i35=i32⋅i2⋅i.
=(i4)8⋅i2⋅i.
=18⋅(−1)⋅i.

What do the i mean in math?

The letter i is used to signify that a number is an imaginary number. It stand for the square root of negative one. In electrical engineering it is often replaced by the letter j to avoid conflict with the symbol for current. See Imaginary numbers.

How much is 2i?

Answer and Explanation: The absolute value of the complex number, 2i, is 2. We can put the complex number, 2i, in the form a + bi by letting a = 0.

What is the value of i raise to 34?

As we know that the even power of -1 gives and 1 and odd power of -1 gives us the value -1. So, here the power is 17 which is an odd number. So, the value of \[{{i}^{34}}=-1\]. So, the value of \[{{i}^{34}}\] is equal to -1.

What is i to an odd power?

In a complex number, i is refered to imaginary number. We know that i = √-1. Hence we observe that we get -1 for even power which clearly shows that we cannot get the same value for odd power. Therefore, if i is raised to an odd power, then it can not simplify to be -1.

What is 4I?

What is the simplified form of I 34?

Algebra Examples Rewrite i34 as (i4)8i2 ( i 4 ) 8 i 2 . Factor out i32 i 32 .

How do you simplify i31?

Algebra Examples Rewrite i31 as (i4)7(i2⋅i) ( i 4 ) 7 ( i 2 ⋅ i ) . Factor out i28 i 28 . Rewrite i28 i 28 as (i4)7 ( i 4 ) 7 . Factor out i2 i 2 .

What does i3 mean in math?

In mathematics, an imaginary number is a number that contains the number i, where i is the imaginary number with value √−1 . By the definition of i, we can calculate powers of i by multiplying √−1 by itself the number of times indicated by the power and using the fact that √−1×√−1=−1 − 1 × − 1 = − 1 to simplify.

How do you solve i35?