What is the latent heat of steam in Btu?
What is the latent heat of steam in Btu?
970.3 BTU per Lb
(Column 6). The latent heat of vaporization of water is at 212°F, 970.3 BTU per Lb.
How do you calculate latent heat of vaporization?
The latent heat equation is heat divided by mass L=Q/m L = Q / m . A latent heat unit is an energy unit per mass unit, like joules per kilogram (J/kg). The latent heat is the heat per unit mass required to trigger a phase change.
How do you calculate steam BTU?
The Conversion Factor For the low-pressure steam typically used in heating systems, that ratio is 1,194 BTUs for every pound of steam the system provides. If your boiler supplies 400 pounds of steam per hour, for example, you would multiply 400 pounds by 1,194 to arrive at a figure of 477,600 BTUs.
How do you calculate latent heat of steam?
Latent Heat ( he ) = hg – hf = 2676 – 419 = 2257 KJ / Kg. Cp – Specific Heat of Steam at Constant Pressure, which can be considered as 1.860 KJ/Kg. °C, Ts – Temperature of super heated Steam, Tf – Saturation temperature i.e., 100°C.
How many Btus does it take to vaporize water?
This heat is called the “latent heat of vaporization”. For water, this is 970 Btu per pound. This change of state is one of the reasons you feel so cold stepping out of a shower. As the water on your skin evaporates, it takes with it 970 Btu per pound of water evaporated.
How many Btus are in a 1 ton steam?
100,000 BTU/h
1 Therm = 100,000 BTU/h. 1 MBH = 1,000 BTU/h.
How do you calculate heat from latent heat?
The Formula for Latent Heat:
- L = \frac{Q}{ M}
- This equation states that the heat Q that must be added or removed for an object of mass m to change phases. We denote Individual latent heat by L.
- L = \frac{Q}{ M}
- = \frac {300}{5}
- = 60 KcalKg^{-1}g.
- Therefore latent heat will be 60 KcalKg{-1}
How do you calculate BTU from flow and temperature?
You can calculate BTU heating or cooling requirements for your process by understanding your application. Some common BTU calculating formulas are shown below. BTU = Flow Rate In GPM (of water) x (Temperature Leaving Process – Temperature Entering Process) x 500.4*Formula changes with fluids others than straight water.
How many BTUs are in a 1 ton steam?
12,000 BTU/h
1 Ton Ac = 12,000 BTU/h Cooling = 15,000 BTU/h Heat Rejection.
How much is latent heat of vaporization?
When a material in liquid state is given energy, it changes its phase from liquid to vapour without change in temperature, the energy absorbed in the process is called latent heat of vaporization. The latent heat of vaporization of water is about 2260kJ/Kg which is equal to 40. 8kJ/mol.
What is latent heat vaporization?
Latent heat of vaporization is a physical property of a substance. It is defined as the heat required to change one mole of liquid at its boiling point under standard atmospheric pressure. It is expressed as kg/mol or kJ/kg.
