How many ways are there to distribute six distinguishable objects into four indistinguishable boxes so that each of the boxes contains at least one object?
How many ways are there to distribute six distinguishable objects into four indistinguishable boxes so that each of the boxes contains at least one object?
=(64)⋅3=45 possibilities. Therefore there are 20+45=65 possible ways to do this.
How many ways can r indistinguishable objects be put into N distinguishable boxes?
32! – Indistinguishable objects and distinguishable boxes: The number of ways to distribute n indistinguish- able objects into k distinguishable boxes is the same as the number of ways of choosing n objects from a set of k types of objects with repetition allowed, which is equal to C(k+n−1,n).
How many ways are there to put 4 indistinguishable balls into 3 indistinguishable boxes?
Example 1 – How many ways are there to put four different balls into three indistinguishable offices without exclusion? This gives us a total of- 1 + 3 + 4 + 6 = 14 ways.
How many ways are there to place 10 distinguishable objects into 8 distinguishable boxes?
Example: How many ways are there to place 10 indistinguishable balls into 8 distinguishable bins? Solution: We have C(10 + 8 – 1, 10) = C(17, 10) = 19,448 ways to arrange 10 indistinguishable balls into 8 distinguishable bins.
How many ways are there to place 8 indistinguishable balls into four distinguishable bins?
Expert-verified answer = 11!/(8!
How many ways are there to place 8 indistinguishable balls in 4 distinguishable bins?
How many ways are there to distribute 5 distinguishable balls into 4 distinguishable boxes so that no box is empty?
=24, for a total of 240.
How many ways are there to distribute five distinguish able objects into three indistinguishable boxes?
Also, the boxes are indistinguishable. So, ans = 7!
How many ways can 5 different balls be distributed among three boxes?
Total , 6 ways.
How many ways can 5 different toys be packed in 3 identical boxes such that no box is empty if any of the boxes may hold all of the toys?
1 option is: 5 C 2 * 3 C 2 2 = 10 * 3 2 = 15 ways.
How many ways can we distribute 5 distinct balls in 3 identical boxes if each box should have at least one ball?
There are 35=243 arrangements if the boxes are numbered.
How many ways 5 balls can be placed in 3 boxes such that no box remains empty if balls are different but boxes are identical?
=3+3=6.
